Three unbiased coins are tossed together find the probability of getting at least two tails

When 3 unbaised coins are tossed, the total number of events = 8

They are {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}

(1) Number of favourable events (getting at least two heads) = 4

  Probability of getting at least two heads = 4/8 = 1/2

(2) At most two heads

That is no head or one head or 2 heads

Probability of getting at most two heads = 7/8

The probability of getting exactly 2 heads is $\frac{1}{2}$

The probability of getting atleast one head is $\frac{5}{8}$

The probability of getting almost 2 tail is $\frac{3}{8}$

The probability of getting exactly one tail is $\frac{3}{8}$