The HCF of two numbers is 12 and their LCM is 360 if one of the numbers is 36 find the other number

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LCM of 36 and 60 is the smallest number among all common multiples of 36 and 60. The first few multiples of 36 and 60 are (36, 72, 108, 144, 180, 216, 252, . . . ) and (60, 120, 180, 240, 300, 360, . . . ) respectively. There are 3 commonly used methods to find LCM of 36 and 60 - by prime factorization, by division method, and by listing multiples.

What is the LCM of 36 and 60?

Answer: LCM of 36 and 60 is 180.

Explanation:

The LCM of two non-zero integers, x(36) and y(60), is the smallest positive integer m(180) that is divisible by both x(36) and y(60) without any remainder.

Methods to Find LCM of 36 and 60

The methods to find the LCM of 36 and 60 are explained below.

• By Prime Factorization Method
• By Division Method
• By Listing Multiples

LCM of 36 and 60 by Prime Factorization

Prime factorization of 36 and 60 is (2 × 2 × 3 × 3) = 22 × 32 and (2 × 2 × 3 × 5) = 22 × 31 × 51 respectively. LCM of 36 and 60 can be obtained by multiplying prime factors raised to their respective highest power, i.e. 22 × 32 × 51 = 180.
Hence, the LCM of 36 and 60 by prime factorization is 180.

LCM of 36 and 60 by Division Method

To calculate the LCM of 36 and 60 by the division method, we will divide the numbers(36, 60) by their prime factors (preferably common). The product of these divisors gives the LCM of 36 and 60.

• Step 1: Find the smallest prime number that is a factor of at least one of the numbers, 36 and 60. Write this prime number(2) on the left of the given numbers(36 and 60), separated as per the ladder arrangement.
• Step 2: If any of the given numbers (36, 60) is a multiple of 2, divide it by 2 and write the quotient below it. Bring down any number that is not divisible by the prime number.
• Step 3: Continue the steps until only 1s are left in the last row.

The LCM of 36 and 60 is the product of all prime numbers on the left, i.e. LCM(36, 60) by division method = 2 × 2 × 3 × 3 × 5 = 180.

LCM of 36 and 60 by Listing Multiples

To calculate the LCM of 36 and 60 by listing out the common multiples, we can follow the given below steps:

• Step 1: List a few multiples of 36 (36, 72, 108, 144, 180, 216, 252, . . . ) and 60 (60, 120, 180, 240, 300, 360, . . . . )
• Step 2: The common multiples from the multiples of 36 and 60 are 180, 360, . . .
• Step 3: The smallest common multiple of 36 and 60 is 180.

∴ The least common multiple of 36 and 60 = 180.

☛ Also Check:

LCM of 36 and 60 Examples

1. Example 1: The GCD and LCM of two numbers are 12 and 180 respectively. If one number is 36, find the other number.

   Solution:

   Let the other number be p.
   ∵ GCD × LCM = 36 × p ⇒ p = (GCD × LCM)/36 ⇒ p = (12 × 180)/36 ⇒ p = 60

   Therefore, the other number is 60.

Show Solution >

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The LCM of 36 and 60 is 180. To find the LCM of 36 and 60, we need to find the multiples of 36 and 60 (multiples of 36 = 36, 72, 108, 144 . . . . 180; multiples of 60 = 60, 120, 180, 240) and choose the smallest multiple that is exactly divisible by 36 and 60, i.e., 180.

If the LCM of 60 and 36 is 180, Find its GCF.

LCM(60, 36) × GCF(60, 36) = 60 × 36 Since the LCM of 60 and 36 = 180 ⇒ 180 × GCF(60, 36) = 2160

Therefore, the GCF = 2160/180 = 12.

How to Find the LCM of 36 and 60 by Prime Factorization?

To find the LCM of 36 and 60 using prime factorization, we will find the prime factors, (36 = 2 × 2 × 3 × 3) and (60 = 2 × 2 × 3 × 5). LCM of 36 and 60 is the product of prime factors raised to their respective highest exponent among the numbers 36 and 60.
⇒ LCM of 36, 60 = 22 × 32 × 51 = 180.

What is the Least Perfect Square Divisible by 36 and 60?

The least number divisible by 36 and 60 = LCM(36, 60)
LCM of 36 and 60 = 2 × 2 × 3 × 3 × 5 [Incomplete pair(s): 5]
⇒ Least perfect square divisible by each 36 and 60 = LCM(36, 60) × 5 = 900 [Square root of 900 = √900 = ±30]
Therefore, 900 is the required number.

What are the Methods to Find LCM of 36 and 60?

The commonly used methods to find the LCM of 36 and 60 are:

• Listing Multiples
• Prime Factorization Method
• Division Method

TCS Company Numerical Ability LCM and HCF

• given n1=36; and n2=??? as we know, n1*n2 = HCF*LCM 36*n2= 12*360

  => n2=120 ;

• 7 years agoHelpfull: Yes(11) No(0)
• Other no = 12*360/36
  =120.
• 7 years agoHelpfull: Yes(1) No(0)
• other no= (12*360)/36=120
• 7 years agoHelpfull: Yes(1) No(0)
• h.c.f*l.c.m=product of two numbers 12*360=36*x

  x=120

• 7 years agoHelpfull: Yes(0) No(0)
• 12*360/36=120
• 7 years agoHelpfull: Yes(0) No(0)
• as we know that hcf * lcm=product of numbers; therefore 12 * 360 = 36 * x

  x=120.

• 7 years agoHelpfull: Yes(0) No(0)
• we know that the product of two numbers=HCF*LCM
  so other number=12*360/36=120
• 7 years agoHelpfull: Yes(0) No(0)
• hcf*lcm = n1+n2 ,so 12*360=36*n2
  i.e,120
• 7 years agoHelpfull: Yes(0) No(0)
• other no=(L.C.M*H.C.F)/one no
  =(12*360)/36=120
• 7 years agoHelpfull: Yes(0) No(0)
• n2=(12*36)/36=120
• 7 years agoHelpfull: Yes(0) No(0)
• number=120; hcf*lcm = multiplication of number; 12*360=x*36;

  x=120;

• 7 years agoHelpfull: Yes(0) No(0)
• as we know hcf*lcm=product of two no. let the no is=x 12*360=36*x =>x=12*360/36

  =>x=120.

• 7 years agoHelpfull: Yes(0) No(0)
• 120 bcoz product of hcf and lcm equals product of two no.
• 7 years agoHelpfull: Yes(0) No(0)
• HCF=12, LCM=360, n1=36,n2=? n1*n2= hcf *lcm, 36*n2=12*360, n2=12*360/36 n2=12*10=120
• 7 years agoHelpfull: Yes(0) No(0)
• Ans:120 36*x=12*360 36*x==4320 x=4320/36 x=120
• 7 years agoHelpfull: Yes(0) No(0)
• L.C.M * H.C.F = Product of two no.s so 2nd no is (12*360)/36

  =120

• 7 years agoHelpfull: Yes(0) No(0)
• HCF=12,LCM=360 We know HCF x LCM = product of two numbers & here one number which is provided is 36.

  Therefore, (360*12)/36= 120 is the answer.

• 4 years agoHelpfull: Yes(0) No(0)