As per the given data the let us calculate the cumulative frequency:
The lower limits of the median class: Here n is even; then the median is given by the mean of (n/2)th observation \(\begin{array}{l}\frac{N}{2}\end{array} \) ⇒ \(\begin{array}{l}\frac{66}{2}\end{array} \) = 33 As 37 is just greater than 33, Therefore, the median class is ’10 – 15′. The lower limits of the median class = 10 The lower limits of the modal class: Modal class=modal class with maximum frequency. Therefore, the modal class is 15 – 20. The lower limit of the modal class is 15. Sum of lower limits of median class and modal class=10 + 15 = 25 The lower limits of the modal class = 25 Explore more such questions and answers at BYJU’S.
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Concept:
Calculation:
Here, N = 66 ∴ N/2 = 33, which lies in the class interval 10-15. So, the lower limit of the median class is 10. Here, the highest frequency is 20, which lies in the class interval 15-20. So, the lower limit of the modal class is 15. So, the required sum is 10 + 15 = 25. Hence, the sum of lower limits of the median class and modal class is 25. India’s #1 Learning Platform Start Complete Exam Preparation
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