The product of two natural numbers is 17.then the sum of the reciprocals of their squares is

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Answered by Guest on 2021-07-10 09:40:36 | Votes 0 | #

290/289

Let the numbers be a and b. Then,

ab = 17, a = 1 and b = 17

So, 1/a2 + 1/b2 = (a2 + b2)/a2 b2
 

= (12 + 172)/(1 * 17)2 = 290/289

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