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Let the length of each train = l Relative speed=\( \Large \left(46-36\right) \times \frac{5}{18}=\frac{25}{9} \) m/sAccording to the question, \( \Large \frac{l+l}{\frac{25}{9}}=36 \)=2l=\( \Large \frac{25}{9} \times 36 =l=50m \) \( \Large \therefore \)length of each train = 50m Part of solved Trains questions and answers : >> Aptitude >> Trains Comments Similar Questions
Exercise :: Problems on Trains - General Questions
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Exercise :: Problems on Trains - General Questions
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Exercise :: Problems on Trains - General Questions
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Exercise :: Problems on Trains - General Questions
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Exercise :: Problems on Trains - General Questions
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Exercise :: Problems on Trains - General Questions |