Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.

Solution

Long Answer

When a dice is rolled once, probability of obtaining six = 

Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.

and probability of obtaining a non-six = 
Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.
Now X can take values 0, 1, 2.P(X = 0) = P(six does not appear a die) = P(non-six on both dice)

                          

Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.

P(X = 1) = P(six appear exactly on one die)                = P(six on first die and non-six on the second die)                                                   + P(six on the second die and non-six on the first die)

              

Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.


P(X = 2) = P(six on both the dice) = 
Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.
∴    probability distribution of X is

Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.

∴            Expectation of X = mean of the variable X

Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.


Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.

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  • Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.
  • Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.
  • Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.
  • Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.
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Two die are thrown simultaneously. If X denote the number sixes, find the expectation of X.

Solution

Let X be the random variable which denotes the number of sixes on two dice. So, X may have values 0,1 or 2.

When a dice is rolled once, probability of obtaining six =16 and probability of obtaining a non-six =55

P(X =0) =P (non-six on both dice)=56×56=2536

P(X=1)=P (six on first and non -six on the second)+P(non-six on the first and six on the second)

=16×56+16×56=1036

P(X=2)=P(six on both the dice) =16×16=136

Therefore, the required probability distribution is as follows:

X 0 1 2P(X)25361036136

Expectation of X=mean of the variable X

=X P(X)=0×2536+1×1036×+2×136=1236=13.


Two dice are thrown simultaneously. if x denotes the number osixes, find the expectation of x.

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