Solution Long Answer
When a dice is rolled once, probability of obtaining six = and probability of obtaining a non-six = Now X can take values 0, 1, 2.P(X = 0) = P(six does not appear a die) = P(non-six on both dice) P(X = 1) = P(six appear exactly on one die) = P(six on first die and non-six on the second die) + P(six on the second die and non-six on the first die)
P(X = 2) = P(six on both the dice) = ∴ probability distribution of X is∴ Expectation of X = mean of the variable X Your browser is no longer supported. Update it to get the best YouTube experience and our latest features. Learn more
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