Two cubes have their volumes in the ratio 1:27. the ratio of their surface area is = ?

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Two cubes have their volumes in the ratio 1:27. the ratio of their surface area is = ?
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Two cubes have their volumes in the ratio 1:27. the ratio of their surface area is = ?

Hence, the volume of the first cube will be ${x^3}{\left( \text{unit} \right)^3}$.And the volume of the second cube will be ${y^3}{\left( \text {unit} \right)^3}$.It is given that the ratio of their volumes is 1:27.\[   \Rightarrow \dfrac{{{\text{Volume of first cube}}}}{{{\text{Volume of second cube}}}} = \dfrac{1}{{27}} \\   \Rightarrow \dfrac{{{x^3}}}{{{y^3}}} = {\left( {\dfrac{x}{y}} \right)^3} = \dfrac{1}{{27}} \\   \Rightarrow \dfrac{x}{y} = {\left( {\dfrac{1}{{27}}} \right)^{\dfrac{1}{3}}} = \dfrac{1}{3} ………....(1) \\ \]Hence the ratio of the side of the first cube to that of the second cube is 1:3.We need to find the ratio of their surface area.By using the above-mentioned formula, we get,Surface area of the first cube $ = 6{x^2}{\left( \text {unit} \right)^2}$Surface area of the second cube $ = 6{y^2}{\left( \text {unit} \right)^2}$Therefore, ratio of their surface area is given by \[ \Rightarrow \dfrac{{{\text{Surface area of first cube}}}}{{{\text{Surface area of second cube}}}} = \dfrac{{6{x^2}}}{{6{y^2}}} = {\left( {\dfrac{x}{y}} \right)^2}\]Using equation (1) in the above, we get \[ \Rightarrow \dfrac{{{\text{Surface area of first cube}}}}{{{\text{Surface area of second cube}}}} = {\left( {\dfrac{x}{y}} \right)^2} = {\left( {\dfrac{1}{3}} \right)^2} = \dfrac{1}{9}\]Hence the ratio of surface area of the first cube to that of the second cube is 1:9.Therefore, option (C). 1:9 is the correct answer.Note: The formula of volume and surface area of the cube should be kept in mind while solving problems like above. Ratio is the quantitative relation between two amounts showing the number of times one value contains or is contained within the other. The unit of both the quantities in the ratio should be the same. In problems like the above effort should be made to obtain the desired result while assuming the minimum number of unknown quantities.

Two cubes have their volumes in the ratio 1 : 27. What is the ratio of their surface areas?

The rate of the value of cubes = 1:27

 `(a_1^3)/(a_2^2) = 1/27`

`a_1 /a_2 = 1/3` …… (i)

Now,

The ratio of their surface area

`s_1 : s_2 = 6a_1^2 :6a_2^2`

 `s_1/s_2 =(6a_1^2)/(6^2)`

      `=(a_1/a_2)^2`

`s_1 /s_2 = 1/9`

Hence, `s_1 : s_2 = 1 : 9`

Concept: Concept of Surface Area, Volume, and Capacity

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Two right circular cylinders of equal volumes have their heights in the ratio 1 : 2. What is the ratio of their radii ?

Let r1 and r2 be the radii of two right circular cylinders and h1 and h2 be the heights.

Since,

Both the cylinder has the same volume.

Therefore,

`pir_1^2 h_1 = pir_2^2 h_2`

`(r_1/r_2)^2 = h^2/h_1`

`(h_1 :h_2 = 1:2 , "given")`

`(r_1/r_2)^2 = (2/1)`

`r_1 :r_2 = sqrt2 : 1`

Concept: Concept of Surface Area, Volume, and Capacity

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Two cubes have their volumes in the ratio 1 : 27. The ratio of their surface areas is a 1 : 3 b 1 : 9 c 1 : 27 d none of these

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