Let the numbers be 3x and 4x. We have; 3x + 4x = 98 7x = 98 x = 98/7 x = 14 Hence, the integers are: 3x = 3*14 = 42 4x = 4*14 = 56 Hope it was helpful... Regards..
Let the numbers be 3x and 4x. We have; 3x + 4x = 98 7x = 98 x = 98/7 x = 14 Hence, the integers are: 3x = 3*14 = 42 4x = 4*14 = 56 Hope it was helpful... Regards.. ?
I think my answer is helpfull
Let the number be x. The sum will be 3x+4x = 98 = 7x =98 = x =14. Therefore the numbers are 3?14 and 4?14 respectively ie 42 and 56
Example2: The sum of two positive integers is 98. The integers are in the ratio 3:4. Find the integers. 2 Answers By Expert Tutors
Matt H. answered • 12/25/17 PATIENT :-) Elem/Middle MATH and WRITING; HS SAT and COLLEGE ESSAYS!
Arturo O. answered • 12/25/17 Experienced Physics Teacher for Physics Tutoring
You appear to have 2 different problem statements, one in the title and one in the description. I will assume the one in the title is correct, and I will work that one. n = 98 - m = 98 - 56 = 42 |