Answer : Let the rates of interest be x% pa and y% pa then, (1500 x x/100 x 3) – (1500 x y/100 x 3) = 27/2 => 45(x - y) = 27/2 => (x -y) = (27/2 x 1/45) = 3/10 = 0.3 Required difference = 0.3%. Hence the answer is (c) Description for Correct answer: Let the rate of interest for two different sources is r1 and r2 respectively.According to question,\( \Large \frac{1500 \times r1 \times 3}{100}-\frac{1500 \times r2 \times 3}{100}\)=13.50\( \Large 4500r1-4500r2=1350 \)\( \Large \left(r1-r2\right)=\frac{1350}{4500} =0.3 \)% Hence,Required difference in rate=0.3% Part of solved Simple and compound interest questions and answers : >> Aptitude >> Simple and compound interest Comments Similar Questions |