If A and B are two events such that P(A) = 0.3 and P(B 0.9 and P(B|A) = 0.6 then P(A|B))

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Text Solution

0.240.30.480.96

Solution : Here, P(A)=0.4,P(B)=0.8andP(A/B)=0.6 <br> `because P(B//A)=(P(BcapA))/(P(A))` <br> `rArr P(BcapA)=P(B//A)cdotP(A)` <br> `=0.6xx0.4=0.24` <br> `thereforeP(AcupB)=P(A)+P(B)-P(AcapB)` <br> `=0.4+0.8-0.24` <br> `=1.2-0.24=0.96`