What is the concentration of a 450 ml solution that contains 1.58 moles of iron II chloride?

Concentration = 1.58⋅mol450×10−3⋅L = 3.5⋅mol⋅L−1 with respect to FeCl2 .

What is the concentration of a solution with a volume of 9ml that contains 2 grams of iron?

2 grams of iron (III) hydroxide constitute 2 / 88.85 = 0.0225 moles. As 9 mL of the solution has 0.0225 moles of iron (III) hydroxide, 1 liter of the solution will have 0.0225*(1000/9) = 2.501 moles.

What is the concentration if I have 450 mL of iron II chloride solution that contains 9.6 grams of iron II chloride solute?

What is the concentration if I have 450 mL of iron (II) chloride solution that contains 9.6grams of iron (II) chloride solute? Given that the molar mass of FeCl2 is 126.75 g/mol, we can determine that we have 0.076 mol FeCl2 solute, which gives us a solution of concentration 0.17 M.

What is the concentration of a solution that contains 450 mL of water and 200.0 grams of iron II chloride?

3.51 m
First, we will use the density (d) of water as 1 g/mL and convert the volume of 450 mL of water into mass (w) of water in kg. Now we will calculate the number of moles (n) of iron(II) chloride. We will calculate the concentration in the form of molality. Hence, the concentration of the solution is 3.51 m.

What is the concentration of a solution that contains 200 grams in a 450 mL solution?

200 g of the compound constitutes 200/126.751 = 1.577 moles. The required concentration of the 450 mL solution that contains 200 g of iron (II) chloride is 3.5 M.

How many grams of ammonium sulfate are needed to make a 0.25 L solution at a concentration of 6.00 m?

0.25 L of a solution with a molarity of 6M has 6*0.25 = 1.5 moles of the solute. The molar mass of ammonium sulfate is 132.14 g/mole. The mass of 1.5 moles is 132.14*1.5 = 198.21 g. Therefore 198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.

What is the concentration of a solution that has a volume of 2.5 l and contains 660 grams of Ca3 PO4 2?

5) What is the concentration of a solution that has a volume of 2.5 L and contains 660 grams of calcium phosphate? Ca3(PO4)2 : 660gx Imol = 2.1278 mol 310.189 2.5L 1.85 m).

Is iron chloride a gas?

Iron(II) chloride, also known as ferrous chloride, is the chemical compound of formula FeCl2. It is a paramagnetic solid with a high melting point. The compound is white, but typical samples are often off-white.

How many grams of nh4 2so4 are needed to make a 0.25 L solution at a concentration of 6 m?

Therefore 198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.

How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution?

5) How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution? Need to add 1200 – 500 = 700 mL.

How many grams of potassium carbonate are needed 200 mL of a 2.5 M solution?

69 grams
We know that in order to calculate a solution’s molarity, you should know the number of moles of solute that is present in 1 L i.e. 1000 mL of solution. Hence, 69 grams of potassium carbonate K2CO3 are needed to make 200 mL of a 2.5 M solution.