This calculator will find the missing variable in the physics equation for Kinetic Energy of a rigid body, when two of the variables are known. Show $$ KE = \dfrac{1}{2}mv^2 $$ Where:
Kinetic EnergyKinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2. We use Joules, kilograms, and meters per second as our defaults, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour, millimeters per second, etc.) could certainly be used as well - the calculation is the same regardless. References/ Further Reading
Question 9 Numericals Next
Answer:
Solution: Weight of truck = Force = 1000 kgf Mass = 1000 kg Initial velocity = 36 km\ h^{-1} = \frac{36\times1000}{60\times60} = 10 m\ s^{-1} New velocity = 72 km\ h^{-1} = \frac{72\times1000}{60\times60} = 20 m\ s^{-1} Work done = Increase in energy = \frac{1}{2}mv^2-\frac{1}{2}mu^2 = \frac{1}{2}m\left(v+u\right)\left(v-u\right) = \frac{1}{2}\times1000\times30\times10 = 150000 J = 1.5\times10^5\ J
Video transcript "Hello students, welcome to nederlands question and answer video. This question looks pretty interesting. And so let's just look at the question is 1000 kg increases exceed the increase in kinetic energy. So he didn't just smart. Lots of the truck is 1000 kg and the initial date so initially it is how much it is pathetic kilometer, but now this we have to convert into meter per second because that will be the standard unit because then only it will tally with this master and teaching and make a positive. Okay, so the second artist 6,000 meters cons are so if I have 3,600 seconds, right? So let's just cancel and see how much we get. So with your we get 10 meter per second as the initial speed. Let me just highlight this so that we don't forget. So this is our initial sweet. This is Amar. Okay, let's go ahead and talk about the next part which is given that is the speed increases or the my Let's see it now becomes saving to two kilometers, but we have to convert it into meter per second. So we know that 72 km/h 70 mm and 100 right there for again just can't allow you to 0 to 36 to 72 such as become 20 meter per second the Canadian Highlander supposed to happen. Use this value rather than the 72 km/h. / okay, we have converted the seeds. We know the mass now. We just need to find the change or increase in kinetic energy. So we need to find what to find screen in kinetic energy. So how do we find this? It will be equal to the kinetic energy. Final Stitch is a final kinetic energy in the initial kinetic energy. Whatever was the change in the time. What is it that does the right thing? So that is what we have to find. Okay. Now this one again moving ahead is a binding energy part. Let's just quickly understand. What do we mean by kind of energy and how they calculated so kind of energy is energy produced by the body emotions anybody which is emotion has a certain mass will always have kinetic energy, which is given as Alpha T Square where m is the mass of the Velocity V the mass of the body we He is a villain of the piece of the body. So let's just write the formula over here as well. So we know that sine is this energy is equal to M. We pray that if you take the initial speed U and the final thing as V. So the final kinetic energy is substitute with substitute this value for the kinetic energy with the final kinetic energy will be half in recess. Because this is a friend of mine, right? So the velocity will be this one - again monsters are scary and it wouldn't do it with the issue of ineffective assistance. So this is what being a difference it's just solid. So let's have em outside creatively Square - useless. We all made that we swim attitude to this half M V plus u into V minus U this week we substitute that Soca. And any was 1000 into V plus u 1 into V minus U was 20 minus 10, which has this is what we got. Okay, so quickly for the service of the CSUN 500 500 into 30 into 10 receiver of the scene and followed. I saw you. So let me write this as 1 Point 5 into 10 to the power 1 2 3 4 5 5 2. This is a change inside energy to just highlight it for you. So this is the answer which we are looking for. So this is the command points. I'd into 10 to the power 5 Joule which is a change in kinetic energy. How did we solve this? We just substituted the values in the final kinetic energy simply subtracted. As your grounding energy from the guards a change in scientific energy. I hope you understood this. If you have any further questions, please post your comments below. Thank you. "
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If you know the initial and final velocity of a car (or whatever) - and the time used - the average acceleration can be calculated as
Common benchmark velocities for acceleration of cars and motorcycles are
Online Car Acceleration Calculatorkm/h Note that force, work and power are calculated for mass acceleration only. Forces due to air resistance (drag) and rolling friction are not included. mphCar Acceleration Diagram - km/hDownload and Print Car Acceleration Chart Car Acceleration Diagram - mphDownload and Print Car Acceleration Chart If you know the distance moved and the time used - the acceleration can be calculated as
Acceleration of some known carsAcceleration ForceThe acceleration force can be calculated as F = m a (3) where F = acceleration force (N, lbf) m = mass of car (kg, slugs) Acceleration WorkThe acceleration work can be calculated as W = F l (4) where W = work done (Nm, J, ft lbf) l = distance moved (m, ft) Acceleration PowerThe acceleration power can be calculated as P = W / dt (5) where P = power (J/s, W, ft lbf/s) Example - Car AccelerationA car with mass 1000 kg (2205 lbm) accelerates from 0 m/s (0 ft/s) to 27.8 m/s (100 km/h, 91.1 ft/s, 62.1 mph) in 10 s. The acceleration can be calculated from eq. 1 as a = ((27.8 m/s) - (0 m/s)) / (10 s) = 2.78 m/s2 The acceleration force can be calculated from eq. 3 as F = (1000 kg) (2.78 m/s2) = 2780 N The distance moved can be calculated by rearranging eq. 2 to ds = a dt2 / 2 = (2.78 m/s2) (10 s)2 / 2 = 139 m The acceleration work can be calculated from eq. 4 as W = (2780 N) (139 m) = 386420 J The acceleration power can be calculated from eq. 5 as P = (386420 J) / (10 s) = 38642 W = 38.6 kW The calculation can also be done in Imperial units: The acceleration can be calculated from eq. 1 as a = ((91.1 ft/s) - (0 ft/s)) / (10 s) = 9.11 ft/s2 In the Imperial system mass is measured in slugs where 1 slug = 32.17405 lbm The acceleration force can be calculated from eq. 3 as F = ((2205 lbm) (1/32.17405 (slugs/ lbm)) ) (9.11 ft/s2) = 624 lbf The distance moved can be calculated by rearranging eq. 2 to ds = a dt2 / 2 = (9.11 ft/s2) (10 s)2 / 2 = 455 ft The acceleration work can be calculated from eq. 4 as W = (624 lbf) (455 ft) = 284075 ft lbf The acceleration power can be calculated from eq. 5 as P = (284075 ft lbf) / (10 s) = 28407 ft lbf/s
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What is the amount of work to be done on a car of mass 1000 kg to increase its velocity from 10 kmph to 20 kmph?
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