Two numbers are in the ratio 2 is to 3 if their LCM is 48 what is the sum of the numbers

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Answer: Option D

Explanation:

Let the numbers be $2x$ and $3x$LCM of $2x$ and $3x$ $=6x~~$ (∵ LCM of 2 and 3 is 6. Hence LCM of $2x$ and $3x$ is $6x$)Given that LCM of $2x$ and $3x$ is 48=> $6x=48$=> $x=\dfrac{48}{6}=8$Sum of the numbers$=2x+3x\\=5x$

= 5 × 8 = 40

Formula for LCM = R1 x R2 x HCFNO1 = R1x HCF; No2 = R2x HCFHence you have to find out the value for HCFLet HCF is unknown factor xGiven LCM = 48, R1 = 2 and R2 = 348 = 2 *3* xx = 8 (HCF)

Sum of two numbers = 2 (8) + 3 (8) = 40

same question ,how do u get 5x .

add 2x and 3x. u ll get 5x. then place 8 in x. then u ll get the answer 40.

Why you have taken L.C.M 2x and 3x while there L.C.M is given in question ?

how do u get 5x 

5x they get becoz they have written they want sum(+) of numbers

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The Lcm of two numbers is 48. If their ratio is 2: 3, find their sum!

Solution

Let 2x & 3x be the numbers their L.C.M will be 6x

But their L.C.M is given = 48

⇒6x = 48

⇒x=8

So, the numbers are 2*8 i.e 16 & 3*8 i.e 24

Hence the sum of numbers = 16+24 =40