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When two fair dice are rolled, what is the probability that at least [#permalink] 08 Jul 2019, 01:27
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Question Stats: 66% (00:54) correct 34% (00:44) wrong based on 113 sessionsHide Show timer StatisticsWhen two fair dice are rolled, what is the probability that at least one of the numbers will be even?(A) 1/4(B) 1/3(C) 1/2(D) 2/3 (E) 3/4 _________________
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Re: When two fair dice are rolled, what is the probability that at least [#permalink] 08 Jul 2019, 01:32
Bunuel wrote: When two fair dice are rolled, what is the probability that at least one of the numbers will be even?(A) 1/4(B) 1/3(C) 1/2(D) 2/3 (E) 3/4 Probability of at least 1 even = 1 - Probability of no even(or Both odd)= 1 - 3/6*3/6 = 1 - 1/4= 3/4IMO Option EPls Hit kudos if you like the solution Posted from my mobile device
Re: When two fair dice are rolled, what is the probability that at least [#permalink] 08 Jul 2019, 01:47
Bunuel wrote: When two fair dice are rolled, what is the probability that at least one of the numbers will be even?(A) 1/4(B) 1/3(C) 1/2(D) 2/3 (E) 3/4 Couple of ways to solve this: Method 1: Case I - Exactly 1 Even (which means that the other one is Odd) = 2C1*3/6*3/6 [2C1 to select which of the two dice would be Even]Case II - Both Even = 3/6*3/6Adding both the cases, we get 18/36 + 9/36 = 27/36 or 3/4Method 2: Probability of No Even = Probability of Both Odd = 3/6*3/6 = 9/36Probability of atleast 1 even = 1 - Probability of No Even = 1 - 9/36 = 27/36 or 3/4Hence, the answer is (E) 3/4PLEASE HIT KUDOS IF YOU LIKE MY SOLUTION
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Re: When two fair dice are rolled, what is the probability that at least [#permalink] 08 Jul 2019, 08:45
Bunuel wrote: When two fair dice are rolled, what is the probability that at least one of the numbers will be even?(A) 1/4(B) 1/3(C) 1/2(D) 2/3 (E) 3/4 getting odd ; 3/6*3/6 ; 1/4atleast 1 even ; 1-1/4; 3/4IMO E
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When two fair dice are rolled, what is the probability that at least [#permalink] 08 Aug 2019, 10:09 Prob of getting at least One even[P(A1E)] = 1- Prob of getting all odd [P(O)]Total number of cases for 2 fair dice roll: 6*6 = 36odd numbers: 1,3,5So 3 cases each > 3*3 = 9 for both dice P(O) = 9/36 => 1/4 Now P(A1E) = 1 - 1/4 => 3/4 Answer: Option E _________________
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Re: When two fair dice are rolled, what is the probability that at least [#permalink] 07 May 2022, 08:31 Hello from the GMAT Club BumpBot!Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________
Re: When two fair dice are rolled, what is the probability that at least [#permalink] 07 May 2022, 08:31 |