> Solution Total number of balls = 8 + 5 = 13 (ii) Favourable number of events for getting red balls = 8C3 P(all 3 balls red) = favourable outcomestotal outcomes=8C313C3 =8!3!×5!×3!×10!13! ⇒P(all 3 balls red)=28143 (iii) Favourable number of events for getting 1 red ball = 8C1 Favourable number of events for getting 2 white balls = 5C2 P(1 red and 2 white balls) = favourable outcomestotal outcomes=8C1×5C213C3 =8!1!×7!×5!2!×3!×3!×10!13! ⇒P(all 3 balls red)=40143 Mathematics RD Sharma XI (2019) All Suggest Corrections
Gate Exam Numerical Ability Probability
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