Question: The mass and the diameter of a planet are three times the respective values for the Earth. The period of oscillation of a simple pendulum on the Earth is $2 \mathrm{~s}$. The period of oscillation of the same pendulum on the planet would be:
Question of from chapter. JEE Main Previous Year 11 Jan 2019, II Correct Option: 4 Solution: Related Questions
90 Qs. 360 Marks 180 Mins
Concept: A simple pendulum is one which can be considered to be a point mass suspended from a string or rod of negligible mass. It is a resonant system with a single resonant frequency. For small amplitudes, the period of such a pendulum can be approximated by Calculation: Period of motion of a pendulum is given by ----(1) On the surface of earth, let period of motion is Te and acceleration due to gravity is ge ----(2) On another planet, let period of motion is TP and gravitational acceleration is gp ----(3) (∴ Pendulum is same, so l will be same) From Equations (2) and (3), ----(4) Now, and Given, Mp = 3Me and Rp = 3Re ----(5) From Equations. (4) and (5) India’s #1 Learning Platform Start Complete Exam Preparation
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