The difference between ages of two persons is 15 years twenty years back

The difference between the ages of two cousins is 10 years. 15 years ago, if the elder one was twice as old as the younger one, find their present ages.

Solution

Let age of elder cousin = x years

and age of younger = (x - 10) years.

15 years ago,

age of older, cousin = x - 15 years

and age of younger = x - 10 - 15

= (x - 25) years.

According to the condition,

x - 15 = 2 (x - 25) $\Rightarrow$ x - 15 = 2x - 50

$\Rightarrow$ 2x - x = 50 - 15 $\Rightarrow$ x = 35

$∴$ Age of elder cousin = 35 years

and age of younger = 35 - 10

= 25 years Ans.

Mathematics
Secondary School Mathematics VIII
Standard VIII

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Home » Aptitude » Problems on Ages » Question

The difference between the ages of two persons is 10 years. 15 years ago the elder one was twice as old as the younger one. The present age of the elder person is ?

1. 25 years
2. 35 years
3. 45 years
4. 55 years

Let the present age of the elder person be x years. Then, the present age of the younger person = (x - 10) years.∵ (x - 15) = 2(x - 10 - 15)⇒ x = 35

∴ the present age of the elder person is 35 years.

Correct Answer:

Description for Correct answer:

Let the present age of the elderly man be x years. The other person age = x - 15. 20 years ago, the elder one was twice as old as the younger one.$ \Large x - 20 = 2 \left(x-15-20\right) $x - 20 = 2x - 70

x = 50

Part of solved Problem on ages questions and answers : >> Aptitude >> Problem on ages

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