Two electric bulbs A and B are marked 220 V, 40 W and 220 V, 60 W respectively. Which one of these bulbs has higher resistance?
Given, two electrical bulbs. P = V 2/R or R = V2/P i.e., R ∝ 1/P.Resistance is inversely proportional to power. Therefore, the first bulb having lesser power has higher resistance.
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If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio of their resistances will be Options(a) (3:2) (b) (2:3) (c) (3:4) (d) (4:3) Correct Answer:(3:2) Explanation:P = V² / R ⇒ R₁ / R₂ = P₂ / P₁ = 60 / 40 = 3 / 2 = 3 : 2 Related Questions: |
If two electric bulbs have 40 w and 60 w rating at 220v then ratio of their resistance will be
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