3 find the values of k for the equation 3x 2 kx 2 0 so that they have two equal roots

I'm a junior in high school. I'm taking Pre-Calculus 11 online and I'm struggling with this question.

For what values of k does 3x2- kx + 2 have two equal real roots?

I've started using b2 - 4ac, but I don't know where to go from there or if that's even the best way to approach this question.

… For what values of k does 3x2- kx + 2 have two equal real roots?

… I know that for a quadratic equation to have 2 equal roots, b2 - 4ac = 0

… k = √24

I don't know how to continue on from there …

Fix the sign issue. Then, do you know how to simplify the radical? (Most instructors would like to see the answers simplified.)

… a=3, b=k, c=2

… k2 - 4(3)(2) = b2 - 4ac

Because -k is squared, in this exercise, you came out okay. Be mindful of coefficient signs. :cool:

I'm a junior in high school. I'm taking Pre-Calculus 11 online and I'm struggling with this question.

For what values of k does 3x2- kx + 2 have two equal real roots?

I've started using b2 - 4ac, but I don't know where to go from there or if that's even the best way to approach this question.

For 3x2 - kx + 2, a=3, b=k, c=2.
I know that for a quadratic equation to have 2 equal roots, b2 - 4ac = 0.
k2 - 4(3)(2) = b2 - 4ac
k2 - 4(3)(2) = 0
k2 -24 = 0
k2 = 24
k =

√24

I don't know how to continue on from there. I would appreciate all the help I can get!

Find both, and simplify the radicals. Otherwise, you're doing fine. I'd do just what you did.