Distribute the referral code to your friends and ask them to register with Tutorix using this referral code. Once we get 15 subscriptions with your referral code, we will activate your 1 year subscription absolutely free. Your subscribed friend will also get 1 month subscription absolutely free.  Text Solution Solution : (a) When a saturated solution of potassium chloride prepared at `60^(@)`C is allowed to cool at room temperature, crystals of potassium chloride will be formed. <br> (b) Initially, sugar will obtained as water wil get evaporated. But on dry heating sugar gets charred and it turns back. <br> `C_(12)H_(22)O_(11)overset(triangle)(to)underset((Black))(12C)+11H_(2)Ouarr.` <br> (c) The black coloured compound, iron sulphide is formed when a mixture of iron filings and sulphur powder is heated strongly. <br> `underset("Iron filings")(Fe)+underset("Sulphur powder")(S) overset(triangle)(to) underset("Iron sulphide")(FeS)` Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts Dedicated counsellor for each student Detailed Performance Evaluation Page 2Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts Dedicated counsellor for each student Detailed Performance Evaluation Answer: (a) Sodium potassium chloride will separate out from the saturated solution when the temperature of the solution reduced from 60°C to room temperature. The solubility of the solid-state is affected by the change in temperature. (b) When aqueous sugar solution is heated first water gets evaporated up to some extent then sugar gets charred. (c) Iron combines with sulphur and forms iron sulphide (FeS). When iron filings and sulphur powder are mixed and heated they undergo a chemical reaction and form ferrous sulphide (FeS). It is a new substance which has properties entirely different from Fe and S.
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What would you observe when a saturated solution of potassium chloride prepared at 600c is allowed to cool to room temperature?
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