What is the mole fraction of 1 molal glucose C6H12O6 solution in water

QUESTION 2.5 A solution of glucose in water is labelled as 10 % w / w. What should be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL 1, then what shall be the molarity of the solution?

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Text Solution

`9.80 m``8.90 m``7.86 m``6.87 m`

Answer : 1

Solution : Glucose is a sugar that occurs in fruits. It is also known as "blood sugar" because it is found in blood and is the body's main sources of energy. If we consider one mole of solution, then it contains `0.150 mol` of glucose and `0.850 mol` of water. We can convert moles of solvent `(H_(2)O)` to kilograms, to calculate the molarity. <br> Mass of `H_(2)O=(n_(H_(2)O))(molar mass_(H_(2)O))` <br> `=(0.850 mol)(18.0 g mol^(-1))` <br> `=15.3 g H_(2)O` <br> Molality of glucose `(C_(6)H_(12)O_(6))` in the solution is <br> `m=n_(glucose)/(g_(H_(2)O)) xx (1000 g)/(kg)` <br> `=(0.150 mol C_(6)H_(12)O_(6))/(15.3 g H_(2)O)xx(1000 g)/(kg)` <br> `=9.80 mol kg^(-1)`