What is the acceleration of a car which starts from rest and acquires a velocity of 40 m/s in 8 s?

A car starting from rest acquires a velocity 180 m s 1 in 0.05 h.Find it's acceleration.

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The Correct Answer is 50 m.

Concept:

• The average acceleration for a given interval is defined as the velocity change for that particular interval.
• Unlike acceleration, for a given interval the average acceleration is determined.
• The average acceleration of an object over a period of time is its velocity change divided by the length of that period.

a = Δv/Δt

Δv = Change in velocity

Δt = The duration of the period

Calculations:

Given that,

The initial velocity u = 0

The final velocity v = 72 km/h = (72) × 5/18 = 20 m/s 

Time t = 5 sec,

To find the distance(S) we need acceleration first,

Acceleration is given by,

a = Δv/Δt

a = (20 - 0)/5

a = 4 m/s2

To find the distance 2nd equation of motion,

S = ut + (1/2)at2

S =  

S = 50 m

The distance travelled by car is 50 m.

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