Q: Two stones A and B are thrown simultaneously from a point on horizontal ground. The stone A is thrown vertically up with velocity uA and the stone B is thrown with speed uB at angle 37° with horizontal . After 0.9 sec stones are moving perpendicular to each other. Then, (a) uA > 9ms-1 (b) uB > 9ms-1 (c) uB= 15ms-1 (d) uB= 9ms-1 Click to See Answer :Sol: Time of Ascent for ball A $\displaystyle t_A = \frac{u_A}{g} $ $\displaystyle \frac{u_A}{g} > 0.9 $ $\displaystyle \frac{u_A}{10} > 0.9 $ $\displaystyle u_A > 9 m/s $ For ball B time of Ascent $\displaystyle t_B = \frac{u_B sin\theta}{g} $ $\displaystyle \frac{u_B sin\theta}{g} = 0.9 $ $\displaystyle \frac{u_B sin37^o}{10} = 0.9 $ $\displaystyle u_B sin37^o = 9 $ $\displaystyle u_B \times \frac{3}{5} = 9 $ $\displaystyle u_B = 15 m/s $ |