Given: ∠A = (3x + 12)˚ and ∠B = (2x - 32)˚ Opposite angles of a parallelogram are equal. ∴ ∠C = ∠A ….(i) ⇒ ∠C = (3x + 12)˚ ∠D = ∠B ….(ii) ∠D = (2x - 32)˚ In a quadrilateral, the sum of all the angles is equal to 360˚. ∴ In ABCD, ∠A + ∠B + ∠C + ∠D = 360˚ ∴ 3x + 12 + 2x - 32 + 3x + 12 + 2x - 32 = 360 10x - 40 = 360 10x = 360 + 40 = 400 ⇒ x = `400/10` = 40 ∴ ∠A = (3x + 12)˚ ∴ ∠A = 3 × 40 +12∴ ∠A = 120 + 12 ⇒ ∠A = 132˚ ∴ ∠C = 132˚ .......[From (i)] ∠B = (2x - 32)˚ ∴ ∠B = 2 × 40 - 32 ∴ ∠B = 80 - 32 ⇒ ∠B = 48˚ ∴ ∠D = 48˚ ........[From (ii)] Hence measure of x is 40. Also, measures of ∠C and ∠D are 132˚ and 48˚ respectively. Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now
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