Given: Ratio of sum of nth terms of 2 AP’s Let us consider 2 AP series AP1 and AP2. Putting n = 1, 2, 3… we get AP1 as 8, 15 22… and AP2 as 31, 35, 39…. So, a1 = 8, d1 = 7 and a2 = 31, d2 = 4 For AP1 S6 = 8 + (11 – 1)7 = 87 For AP2 S6 = 31 + (11 – 1)4 = 81 Required ratio = 8781=2927> Suggest Corrections |