Tags: Class 7 , Maths , Lines and Angles Asked by Vanshika Singh
Let one of the angles be x. Two complementary angles differ by = 12. Bigger angle = (x + 12). Complementary angles = 90. x + x + 12 = 90 2x + 12 = 90 2x = (90 – 12) 2x = 78 x = 78 / 2 x = 39 = smallest angle (x + 12) = 39 + 12 = 51 = biggest angle The angles are 39, 51 degrees respectively.
> Solution Two angels are said to be complementary when their sum is 90° Let one angle be x then other will be (x -12°) A/q, x + ( x-12°) = 90° ( complementary angles) ⇒ 2x - 12°= 90° ⇒2x = 90° + 12° ⇒2x = 102 ⇒x = 51° and (x-12 ) = 51 - 12 = 39° ∴ angles are 39° and 51° Suggest Corrections 0 The difference in the measures of two complementary angles is 12. Find the measures of the angles?
Let the two angles be x and yGiven, x-y=12We know that the sum of complementary angles is 90Therefore, x+y=90so, x=90-ySubstitute x in x-y=12Therefore, 90-y-y = 12 90-2y = 12 -2y = 12 - 90 -2y = -78 y = -78/-2 y = 39Substitute y in x - y = 12 x - 39 = 12 x = 12+39 x = 51Therefore, the two angles are 51 degree and 39 degree. |