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Ammy C. asked • 09/09/17
Can you please explain I have no idea and im kinda confused ## 2 Answers By Expert Tutors
(4 choose 2) = 4!/(2!)(2!) = 24/(2*2) = 24/4 = 6 (4 choose 3) = 4!/(3!*1!) = 24/6 = 4
Let's look a the question this way. Each coin can land on a heads or a tails Here are the possibilities. (Each letter is another coin.) One Tail/3 heads - 4 ways Two Tails/ two heads - 6 ways At least 2 heads means 2 heads or 3 heads or 4 heads There are 6 ways to get 2 heads, 4 ways to get 3 heads and 1 way to get 4 heads. This is a total of 6+4+1 = 11 ways to get at least 2 heads. Last updated: 7/13/2022 If you toss 5 fair coins, in how many ways can you obtain at least two heads? ("At least two" is the complement of "zero or one.") Show Answer Create an account. Get free access to expert answers - Get 3 free question credits
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$\binom{10}0 = 1 \rightarrow $ no tails $\binom{10}1 = 10 \rightarrow $ one tail only $2^{10} = 1024$ $1024-11 = 1013 $ $\endgroup$ 4 The ratio of successful events A = 26 to the total number of possible combinations of a sample space S = 32 is the probability of 2 heads in 5 coin tosses. Users may refer the below solved example work with steps to learn how to find what is the probability of getting at-least 2 heads, if a coin is tossed five times or 5 coins tossed together. Users may refer this tree diagram to learn how to find all the possible combinations of sample space for flipping a coin one, two, three or four times.
Step by step workout step 2 Find the expected or successful events A A = {HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, TTHHH, TTHHT, TTHTH, TTTHH} A = 26step 3 Find the probability P(A) = Successful Events/Total Events of Sample Space = 26/32 = 0.81 P(A) = 0.81 0.81 is the probability of getting 2 Heads in 5 tosses. |