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Given: 6, 7, 8, 9, and 12. Concept used: The least common multiple (LCM) of a set of numbers is the smallest number that leaves 0 as the remainder each time when divided by any of those numbers. Calculation: LCM (6, 7, 8, 9 12) = 504 So, 504 is the smallest number that leaves 0 as the remainder each time when divided by any of 6, 7, 8, 9, and 12. So, the required number = (504 + 2) = 506 ∴ 506 will be the smallest number which when divided by 6, 7, 8, 9, and 12 leaves the remainder 2 each time. India’s #1 Learning Platform Start Complete Exam Preparation
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