$\begingroup$
I'm reading a book (Calculus Made Easy - Silvanus Thompson) that has the following exercise:
It's part of a chapter that explains how to find minima/maxima using second-order derivatives. I'm quite confused on how to solve this problem. I tried calculating the derivative of the following: $$y = 3(xN)^2 + 2[(1-x)N]^2$$ Where $x$ represents a certain percentage of $N$. This gave me: $$\frac{dy}{dx} = 2N(5x-2)$$ Which I then equated to $0$, which gave me the wrong value for $x$ when comparing to the answer key (which is $0.4N, 0.6N$). Clearly I'm doing it wrong. Any help would be greatly appreciated. Please bear in mind that I'm trying to learn this stuff by myself without any proper math background. $\endgroup$ 5Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Page 2Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Page 3Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Page 4Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now |
Divide $112 into two parts in such a way that 13/5 of one part is equal to three times the other.
zusammenhängende Posts
Urheberrechte © © 2024 frojeostern Inc.
