Consider the two vectors A and B the magnitude of their sum

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According to question the sum of two vectors is equal to resultant R and

R =A→ +B→R =A→ +B→ (taking mod to both sides)R2 =A→ +B→2 R =A2+B2+2ABcosθ

here θ is the angle between both vector A and B , but in question only given
A→ > B→ which just clears that the magnitude of vector A is greater than magnitude of vector B
if we put the numerical values in the resultant formula we will get the desired result.

The magnitude of their sum is| R| = (|A|2+|B|2 + 2 .| A| .| B| . cosθ)(1 / 2 )whereθ is the angle between the vectors A and B .It has no relevance with what is greater of smaller vector .It can applied anywhere.