Answered by Guest on 2018-01-20 03:14:23 | Votes 32 | # Let the CP of article A be Rs.x CP of article B = Rs.(5000 - x) According to the question, 120% of x + 90% of (5000 - x) = 102% of 5000 120x + 450000 - 90x = 510000 30x = 510000 - 450000 = 60000 x = 6000 / 30 = Rs.2000
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Questions : A person bought two articles A and B for Rs.5,000. He sold A at 20% profit and B at 10% loss. He thus gained 2% on his outlay. The cost price of A was (a) Rs.3,500 (b) Rs.2,000 (c) Rs.2,500 (d) Rs.3,000 Answer: (b) Let the CP of article A be Rs.x CP of article B = Rs.(5000 - x) According to the question, 120% of x + 90% of (5000 - x) = 102% of 5000 120x + 450000 - 90x = 510000 30x = 510000 - 450000 = 60000 x = $60000/30$ = Rs.2000
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Given that , CP of two articles A and B = $ 5,000Let the CP of article A be $ y∴ CP of article B = $ (5000 – y)According to the question,120% of y + 90% of (5000 – y) = 102% of 5000⇒ 120y + 450000 – 90y = 510000⇒ 30y = 510000 – 450000 = 60000 Hence , The cost price of A is $ 2000 .
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