Write the linear equation such that each point on its graph has ordinate two times its abscissa

Let the abscissa of the point be x,

Ordinate (y) = 3x Abscissa ⇒ y = 3x When x = 1, then y = 3 × 1 = 3 and when x = 2, then y = 3 × 2 = 6.

Here, we find two points A (1, 3) and B (2, 6). So, draw the graph by plotting the points and joining the line AB.

Text Solution

Solution : Let the abscissa of the point be x, <br> According to the question, Ordinate `(y)=3xx " Abscissa" implies y=3x` <br> When x=1, then `y=3xx1=3` and when x=2, then `y=3xx2=6` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NCERT_EXE_MATH_IX_C04_S01_031_S01.png" width="80%"> <br> Here, we find two points A (1, 3) and B (2, 6). So, draw the graph by plotting the points and joining the line AB. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NCERT_EXE_MATH_IX_C04_S01_031_S02.png" width="80%"> <br> Hence, y=3x is the required equation such that each point on its graph has an ordinate 3 times its abscissa.

Write the linear equation such that each point on its graph has an ordinate 3 times its abscissa. Maths Q&A

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