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Option 3 : A straight line parallel to the time axis
CONCEPT: Velocity:
Uniform motion
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warning Report Error Page 22Answer: Given, the car starts from rest, so its initial velocity u = 0 Acceleration, (a) and time (t) = 8 s From first equation of motion, v = u + at On putting a and t = 8 s in above equation, we get So, final velocity v is Again, from second equation of motion, On putting t = 8 s and a = 5 ms"2 in above equation, we get So, the distance covered in 8 s is 160 m. Given, total time t = 12 s. After 8 s, the car continues with constant velocity i.e., the car will move with a velocity of . So, remaining time t'= 12 s - 8 s = 4 s The distance covered in the last 4s (s') = Velocity x Time [ Distance = Velocity x Time] = 40 x 4 = 160 m [We have used the direct formula because after 8 s, car is moving with constant velocity i.e., zero acceleration]. Total distance travelled in 12 s from the start D = s + s' = 160 + 160 = 320m Page 23
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