When the sun is 30º above the horizontal, Find the length of shadow cast by a building 50m high Let AB be the building and AC be its shadow. Then, AB = 50 m and θ = 30º. `\therefore \frac{AC}{AB}=\text{cot 3}0^\text{o}=\sqrt{3}` `\Rightarrow \frac{AC}{50}=\sqrt{3}` ⇒ AC = 50√3 cm. Concept: Heights and Distances Is there an error in this question or solution? |