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1-Does a reaction occur when aqueous solutions of calcium chloride and lead(II) nitrate are combined? If a reaction does occur, write the net ionic equation. Does a reaction occur when aqueous solutions of potassium sulfide and ammonium nitrate are combined? If a reaction does occur, write the net ionic equation. Does a reaction occur when aqueous solutions of potassium carbonate and iron(II) nitrate are combined? If a reaction does occur, write the net ionic equation. Does a reaction occur when aqueous solutions of iron(II) nitrate and sodium sulfate are combined? If a reaction does occur, write the net ionic equation. Does a reaction occur when aqueous solutions of sodium carbonate and lead(II) nitrate are combined? If a reaction does occur, write the net ionic equation. Does a reaction occur when aqueous solutions of sodium carbonate and lead(II) nitrate are combined? If a reaction does occur, write the net ionic equation.
Having knowledge of precipitation reactions to predict when they will occur is a powerful tool in extraction of metals and salts from solution. If you know what ions are present, then you can design a series of precipitation reactions to extract the specific one that you want. For an example of this in action click to see the extraction and quantification of sulfate in fertiliser experiment. Let's examine a precipitation reaction that occurs within aqueous solution. A solution is formed when a solute (in this case a salt, like CuSO₄) is dissolved in a solvent (water). The water molecules are small, and have polar regions which have a slight positive and negative charge on either side which enables the molecule to move between and surround the ions, stick to their charges, and separate them (Taylor, 2007, p.294-295). Salts are ionic compounds; compounds that are made out of Cations (positively charged ions), and Anions (negatively charged ions). When the water molecules move in between the ionic bonds, these cations and anions separate from each other. This process is known as dissociation (Taylor, 2007, p.295). CuSO₄ (s) + H₂O (l) → Cu²⁺ (aq) + SO₄²⁻ (aq) This means, that when any combination of salt solutions are mixed, these compounds exist in their dissociated form as ions. NaCl (aq) + CuSO₄ (aq) → Na⁺ (aq) + Cl⁻ (aq) + Cu²⁺ (aq) + SO₄²⁻ (aq) Ions remain in solution (meaning, dissolved in water) because the attraction forces between the ions and the water is greater than the attraction forces between the ions and other ions. Conversely, ions will come out of solution (forming a precipitate) if the attraction forces are greater between the ions and other ions. This is like a situation where your family (mum, dad, brothers and sisters) may dissociate from each other and mingle when at a family barbecue - whether you choose to stick together or not depends on how much you like to hang out with the other people there.But how can we check whether the ions present in our mixture of salts like to hang out with each other more than with the solvent? Tables of data have been collected from many experiments of all sorts of combinations of ions such that we can simply look them up to determine whether any of the ions present will produce a solid. These are known as solubility tables of ions.
Copper chloride, the other possibility, we read the row on the table for chlorides and find that they are soluble in anything except when combined with silver, lead, mercury, or copper cations. So Copper chloride will also remain in solution. Now that all possibilities have been ascertained, there will be no precipitates formed, and hence no reaction would occur to change their chemical composition. So our original example from above was correct in stating that all the ions are aqueous. NaCl (aq) + CuSO₄ (aq) → Na⁺ (aq) + Cl⁻ (aq) + Cu²⁺ (aq) + SO₄²⁻ (aq) Let's try another example; NaCl (aq) + AgNO₃ (aq) → Na⁺(aq) + Cl⁻(aq) + Ag⁺(aq) + NO₃⁻(aq) First we determine what are the possible combinations of these cations and anions could be:
The complete chemical equation now becomes: NaCl (aq) + AgNO₃ (aq) → NaNO₃ (aq) + AgCl (s) At this point, you may have noticed that the products look very similar to the reactants, only that the anions have swapped partners. Sodium (Na⁺) has swapped its Chloride (Cl⁻) partner for a Nitrate (NO₃⁻) partner instead, and similarly the Silver has swapped the Nitrate partner for a Chloride ion. This observation can save you some time because if there is any reaction occurring at all, then the anions will have exchanged places - simply look these products up on the solubility table and determine whether they are soluble or not. 1. A common error that I see when students write these equations down, is they forget to assign the physical states of matter to each formula that appears in the equation (a formula is things like NaCl, H₂O, Na⁺). This is especially important for precipitation reactions where there is likely to be one substance that has changed from an aqueous phase to a solid phase and this needs to be clearly labelled. For example;
2. The second common error is forgetting that compounds are neutrally charged unless they have become ions. This means that you have to make sure the charges of the cation and anion add up to zero. For example:
3. The third common error is forgetting to balance the overall equation. Once you have written all the reactants and products, specified which are aqueous and which are solids, it is easy to overlook the fact that the number of atoms on the left and right sides of the equation are not always equal anymore. For example:
Most chemistry textbooks will have practice problems like this so check those first. If you would like to read some alternative explanations as well as practice problems then visit some of these websites: Linstead, G, 2011. Pearson Science 10 Student Book. 1st ed. Melbourne: Pearson Australia. |