What will be the uncertainty in velocity of an electron if uncertainty in its position is 1 angstrom

Text Solution

Solution : According to Heisenberg uncertainty principle, <br> `Deltax gt Deltap ge (h)/(4pi) or Deltax xx mDeltav ge (h)/(4pi)` <br> The uncertainty in position, `Deltax=1`Å=`10^(-10)m` <br> thus, `Deltav=(h)/(Deltax xxmxx4pi)=(6.626xx10^(-34))/(10^(-10)xx9.1xx10^(-31)xx4pi)` <br> `=5.794xx10^(5)m*s^(-1)`