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What will be the amount of zinc required to produce 1.12 ml hon STP in the process with dilute HCI?

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Zn + 2HCl ---> ZnCl₂ + H₂1mole of Zn produces 1 mole of H₂1mole of Hydrogen gasoccupies 22.4lit ( 0r 22400ml)at STP.22400ml of Hydrogen gas is produced from 1mole of Zn(65g)22400ml of H₂ ------> 65g of Zn1.12ml of H₂ -----?=( 65*1.12)/22400= 3.25 x 10⁻³g=32.5x 10⁻⁴g∴AMOUNT OF Zn required is

32.5x 10⁻⁴g

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The amount of zinc required to produce 1.12 mL of H2 at STP on treatment with dil. HCl will be: Given: Molar mass of Zn= 65 g/mol

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