What is wavelength of a particle of mass 1g moving with a velocity of 200 m s?

  • State the de Broglie wave equation.
  • Use this equation to calculate the wavelength of a moving object.

Bohr’s model of the atom was valuable in demonstrating how electrons were capable of absorbing and releasing energy and how atomic emission spectra were created. However, the model did not really explain why electrons should exist only in fixed circular orbits rather than being able to exist in a limitless number of orbits all with different energies. In order to explain why atomic energy states are quantized, scientists needed to rethink the way in which they viewed the nature of the electron and its movement.

Planck’s investigation of the emission spectra of hot objects and the subsequent studies into the photoelectric effect had proven that light was capable of behaving both as a wave and as a particle. It seemed reasonable to wonder if electrons could also have a dual wave-particle nature. In 1924, French scientist Louis de Broglie (1892–1987) derived an equation that described the wave nature of any particle. Particularly, the wavelength (λ) of any moving object is given by:

λ=hmv\displaystyle\lambda=\frac{h}{mv}λ=mvh

In this equation, h is Planck’s constant, m is the mass of the particle in kg, and v is the velocity of the particle in m/s. The problem below shows how to calculate the wavelength of the electron.

An electron of mass 9.11 × 10−31 kg moves at nearly the speed of light. Using a velocity of 3.00 × 108 m/s, calculate the wavelength of the electron.

Step 1: List the known quantities and plan the problem.

Known
  • mass (m) = 9.11 × 10−31 kg
  • Planck's constant (h) = 6.6262  10−34 × J · s
  • velocity (v) = 3.00 × 108 m/s
Unknown

Apply the de Broglie wave equation 

λ=hmv\displaystyle\lambda=\frac{h}{mv}λ=mvh

to solve for the wavelength of the moving electron.

Step 2: Calculate

λ=hmv=6.626×10−34J⋅s(9.11×10−31 kg)×(3.00×108 m/s)=2.42×10−12 m\displaystyle\lambda=\frac{h}{mv}=\frac{6.626\times10^{-34}\text{J}\cdot\text{s}}{\left(9.11\times10^{-31}\text{ kg}\right)\times\left(3.00\times10^8\text{ m/s}\right)}=2.42\times10^{-12}\text{ m}λ=mvh=(9.11×1031 kg)×(3.00×108 m/s)6.626×1034Js=2.42×1012 m

Step 3: Think about your result.

This very small wavelength is about 1/20th of the diameter of a hydrogen atom. Looking at the equation, as the speed of the electron decreases, its wavelength increases. The wavelengths of everyday large objects with much greater masses should be very small.

If we were to calculate the wavelength of a 0.145 kg baseball thrown at a speed of 40 m/s, we would come up with an extremely short wavelength on the order of 10−34 m. This wavelength is impossible to detect even with advanced scientific equipment. Indeed, while all objects move with wavelike motion, we never notice it because the wavelengths are far too short. On the other hand, particles with measurable wavelengths are all very small. However, the wave nature of the electron proved to be a key development in a new understanding of the nature of the electron. An electron that is confined to a particular space around the nucleus of an atom can only move around that atom in such a way that its electron wave “fits” the size of the atom correctly. This means that the frequencies of electron waves are quantized. Based on the E = hv equation, the quantized frequencies means that electrons can only exist in an atom at specific energies, as Bohr had previously theorized.

What is wavelength of a particle of mass 1g moving with a velocity of 200 m s?
Figure 1. The circumference of the orbit in (A) allows the electron wave to fit perfectly into the orbit. This is an allowed orbit. In (B), the electron wave does not fit properly into the orbit, so this orbit is not allowed.

  • The deBroglie wave equations allows calculation of the wavelength of any moving object.
  • As the speed of the electron decreases, its wavelength increases.

Use the link below to practice calculations using the deBroglie wave equation: http://science.widener.edu/svb/tutorial/debrogliecsn7.html

  1. What did the Bohr model not explain?
  2. State the deBroglie wave equation.
  3. What happens as the speed of the electron decreases?

  • de Broglie wave equation: 

    λ=hmv\displaystyle\lambda=\frac{h}{mv}λ=mvh

  • quantize: Limit the possible values of (a magnitude or quantity) to a discrete set of values by quantum mechanical rules.

CC licensed content, Shared previously