(i)First find the prime factors of 675 675 = 3 × 3 × 3 × 5 × 5 = 33 × 52 Since 675 is not a perfect cube. To make the quotient a perfect cube we divide it by 52 = 25, which gives 27 as quotient where, 27 is a perfect cube. ∴ 25 is the required smallest number. (ii) 8640 First find the prime factors of 8640 8640 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5 = 23 × 23 × 33 × 5 Since 8640 is not a perfect cube. To make the quotient a perfect cube we divide it by 5, which gives 1728 as quotient and we know that 1728 is a perfect cube. ∴5 is the required smallest number. (iii) 1600 First find the prime factors of 1600 1600 = 2 × 2 × 2 × 2 × 2 × 2 × 5 × 5 = 23 × 23 × 52 Since 1600 is not a perfect cube. To make the quotient a perfect cube we divide it by 52 = 25, which gives 64 as quotient and we know that 64 is a perfect cube ∴ 25 is the required smallest number. (iv) 8788 First find the prime factors of 8788 8788 = 2 × 2 × 13 × 13 × 13 = 22 × 133 Since 8788 is not a perfect cube. To make the quotient a perfect cube we divide it by 4, which gives 2197 as quotient and we know that 2197 is a perfect cube ∴ 4 is the required smallest number. (v) 7803 First find the prime factors of 7803 7803 = 3 × 3 × 3 × 17 × 17 = 33 × 172 Since 7803 is not a perfect cube. To make the quotient a perfect cube we divide it by 172 = 289, which gives 27 as quotient and we know that 27 is a perfect cube ∴ 289 is the required smallest number. (vi) 107811 First find the prime factors of 107811 107811 = 3 × 3 × 3 × 3 × 11 × 11 × 11 = 33 × 113 × 3 Since 107811 is not a perfect cube. To make the quotient a perfect cube we divide it by 3, which gives 35937 as quotient and we know that 35937 is a perfect cube. ∴ 3 is the required smallest number. (vii) 35721 First find the prime factors of 35721 35721 = 3 × 3 × 3 × 3 × 3 × 3 × 7 × 7 = 33 × 33 × 72 Since 35721 is not a perfect cube. To make the quotient a perfect cube we divide it by 72 = 49, which gives 729 as quotient and we know that 729 is a perfect cube ∴ 49 is the required smallest number. (viii) 243000 First find the prime factors of 243000 243000 = 2 × 2 × 2 × 3 × 3 × 3 × 3 × 3 × 5 × 5 × 5 = 23 × 33 × 53 × 32 Since 243000 is not a perfect cube. To make the quotient a perfect cube we divide it by 32 = 9, which gives 27000 as quotient and we know that 27000 is a perfect cube ∴ 9 is the required smallest number.
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Answer:
(i) 675 First find the factors of 675 675 = 3 × 3 × 3 × 5 × 5 = 33 × 52 ∴To make a perfect cube we need to multiply the product by 5. (ii) 1323 First find the factors of 1323 1323 = 3 × 3 × 3 × 7 × 7 = 33 × 72 ∴To make a perfect cube we need to multiply the product by 7. (iii) 2560 First find the factors of 2560 2560 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 5 = 23 × 23 × 23 × 5 ∴To make a perfect cube we need to multiply the product by 5 × 5 = 25. (iv) 7803 First find the factors of 7803 7803 = 3 × 3 × 3 × 17 × 17 = 33 × 172 ∴To make a perfect cube we need to multiply the product by 17. (v) 107811 First find the factors of 107811 107811 = 3 × 3 × 3 × 3 × 11 × 11 × 11 = 33 × 3 × 113 ∴To make a perfect cube we need to multiply the product by 3 × 3 = 9. (vi) 35721 First find the factors of 35721 35721 = 3 × 3 × 3 × 3 × 3 × 3 × 7 × 7 = 33 × 33 × 72 ∴To make a perfect cube we need to multiply the product by 7.
Was This helpful? Text Solution Solution : By using prime factorization we could find:<br>(i)`7803`<br>`675=3^3times17^2`<br>As we can see that `17` is not cubed.<br>Hence, `17` is the smallest number by which `7803` should be multiplied to make it a perfect cube.<br><br>(ii)`107811`<br>`107811=3^3times3times11^3`<br>As we can see that `3` is not cubed.<br>Hence, `3` is the smallest number by which `107811` should be multiplied to make it a perfect cube.<br>(iii)`35721`<br>`35721=3^6times7^2`<br>As we can see that `7` is not cubed.<br>Hence, `7` is the smallest number by which `35721` should be multiplied to make it a perfect cube. |