What is the probability of getting consonant from number?

1. Raw Data:

Numerical observations collected by an observer is called raw data.

2. Frequency and Frequency Distribution:

(i) The number of times an observation occurs in the given data is called the frequency of the observation.

(ii) A way of presenting data that exhibits the values of the variable and corresponding frequencies is called a frequency distribution.

3. Histogram:

Grouped data can be presented using a histogram. The histogram is a type of bar diagram, where the class intervals are shown on the horizontal axis and the heights of the bars show the frequency of the class interval. Also, there is no gap between the bars as there is no gap between the class intervals.

4. Pie Chart:

Data can also be presented using a circle graph or pie chart. A circle graph shows the relationship between a whole and its part.

5. Events in an Experiment:

(i) An outcome of a random experiment is called an elementary event.

(ii) An event obtained by combining two or more elementary events is known as a compound event.

(iii) An event, associated with a random experiment, is said to occur if any one of the elementary events associated with the event is an outcome.

6. Probability of an Event:

If there are n elementary events associated to a random experiment such that m of them are favourable to an event A, then Probability of happening of A=mn=Favourable number of elementary eventsTotal number of elementary events

7. For any event A, we have pA+pA¯=1

Answer:

Total numbers of letters: 26

Total number of consonants:21

Hence, the required probabilty is 21/26

Step-by-step explanation:

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We know the sum of probabilities is equal to one. When choosing a letter from English alphabet at random, there are only two possibilities; either vowel or consonant. Since there are five vowels, the probability of getting a vowel is 526. So the probability of getting consonant is 1−526=2126.

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  di ako magaling kase sa english

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  a e i o u consonant. alphabet letter 26 26-5=21

Solution:

Given, a letter of English alphabets is chosen at random.

We have to determine the probability that the letter is a consonant.

There are 26 English alphabets which consist of 5 vowels and 21 consonants.

The probability of selecting a letter that is a consonant is given by

Favourable outcomes = b, c, d, f, g, h , j, k , l, m, n, p, q, r, s, t, v, w, x, y, z

Number of favourable outcomes = 21

Number of possible outcomes = 26

Probability = number of favourable outcomes / number of possible outcomes

Probability = 21/26

Therefore, the probability of choosing an alphabet that is a consonant is 21/26.

✦ Try This: A letter of English alphabets is chosen at random. Determine the probability that the letter is a vowel.

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 14

NCERT Exemplar Class 10 Maths Exercise 13.3 Problem 33

Summary:

A letter of English alphabets is chosen at random. The probability that the letter is a consonant is 21/26

☛ Related Questions:

Formula used:

Probability = Total number of outcomes/ Sample space

Calculation:

Sample space = {p, h, o, t, o, s, y, n, t, h, e, s, I, s}

⇒ Sample space = 14

Possibility of outcomes = {P, h, t, s, y, n, t, h, s, s}

⇒ Possibility of outcomes = 10

Required probability = 10/ 14

∴ required probability = 5/ 7