What is the nature and size of the image formed when an object is placed at C in front of a concave mirror?

Edited by Sim, Jen Moreau

Is defined as a spherical mirror with a polished inner side.

The type of images formed by a concave mirror depends on the position of the object to the mirror. If the distance of an object say OO' from a concave mirror is changed, then the nature, size, and location of the image are also changed.

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Formation of different images depending on the position of the object are shown below:.

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Categories : Physics

Recent edits by: Sim

3. Find the image's size, nature and position formed when an object of size 1 cm is placed at a distance of 25 cm from a concave mirror of a focal length of 20 cm?

Sol: Here we have been given the object distance and focal length, so first of all, we will find out the image distance which will give us the position of the image.

(i) Position of image

Here, Object distance, u	=	− 25 cm (To the left of the mirror)
Image distance, v	=	? (To be calculated)
And, Focal length, f	=	− 20 cm (It is a concave mirror)
Now, putting these values in the mirror formula :
1/f	=	1/v + 1/u
We get: 1/–20	=	1/v + 1/– 25
(or) – 1/20	=	1/v – 1/25
(or) 1/v	=	1/25 – 1/20
	=	4 – 5/100
	=	– 1/100
So Image distance, v	=	− 100cm

Thus, the position of the image is 100 cm to the left side of the mirror or 100 cm in front of the mirror (the minus sign shows the left side of the mirror).

(ii) Nature of image

Since the image is formed in front of the concave mirror, its nature will be "Real and Inverted".

(iii) Size of image

To find the size of the image, we will have to calculate the magnification first.

The magnification produced by a mirror is given by :
m	=	v/u
Here is the image distance, v	=	− 100cm
Object distance, u	=	− 25cm
So, m	=	– (–100) / (– 25) = –4
Magnification,m	=	−4
We also have another formula for magnification, which is :
m	=	h2/h1
Here, Magnification,m	=	−4 (Found above)
Height of image,h2	=	? (To be calculated)
Height of object,h1	=	1cm (Given)
Now, putting these values in the above magnification formula, we get:
– 4	=	h2/1