What is the force acting on the particle if the motion of the particle is given as Y UT 1 2gt² *?

Tags: Class 11 , Physics , Laws of Motion     Asked by Vagmita Pandya    

• y = ut + ½ gt2

  Differentiate y with respect to t which gives velocity as dy/dt = v

  dy/dt = u + ½ g (2t)

  v=u + gt -------------------Eqn (1) 

  Differentiate v with respect to t which gives velocity as d2y/dt2 = dv/dt = a

  dv/dt = 0 + g

  a = g  ----------------------Eqn (2)

  We know that force acting on a mass m is given by F = ma

  Now from Eqn (2), substitute a =g, Hence, F = mg

  Answered on: 2018/02/02 by ExamFear Education    

  
  
  

The motion of a particle of mass m is described by y = ut +1 / 2 g ∧∧ 2 . Find the force acting on the particle

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Text Solution

Solution : Here, ` y = ut + (1)/(2) g t^(2) ` <br> ` velocity , upsilon = (dy)/(dt)=u+ (1)/(2) g (2t)= u + g t , ` <br> acceleration `a = (du)/(dt) = 0 + g = g ` <br> ` As F= ma :. F = mg ` <br> Thus the given equation describes the motion of a partical under acceleration due to gravity , and y is the position co- ordinate in the direction of g .