What amount of pure acid must be added to 600 ml of a 35% acid solution to produce a 50% acid solution?

Allie H.

asked • 02/05/16

1 Expert Answer

Adam K. answered • 02/05/16

Central Catholic Math Teacher/Department Head

So 1x + .5(300) = .6(x + 300)

This formula is in other words: 100% of x ml are added to 50% of 300ml to get 60% of the total (x+300)

Solving this gets you x = 75ml

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What quantity of pure acid must be added to 600mL of a 45% acid solution to produce a 70% acid solution

x + .45(600) = .70(600+x)

x + 270 = 420+.70x

.30x + 270 = 420

.30x = 150

x = 500 mL

Give a variable to how much pure acid. Let y = volume in mL of pure acid to add.

Note that amount of acid in mixture or resulting solution will be

and volume of resulting solution will be

mL. We must assume you mean your concentration as volume/volume; otherwise, you will need the densities of your pure acid and of the 50% solution.

In your simplified description, your equation is

;

mL of the pure acid.