Two sound waves in air have wavelength ratio 1:3. then their frequency ratio will be

Two waves of the same pitch have amplitudes in the ratio 1: 3 What will be the ratio of their (i) loudness, (ii) pitch?

(i) Loudness ∝ (amplitude)2

Loudness is proportional to amplitude square Ratio of loudness =`"L"_1/"L"_2 =((a_1)^2)/((a_2)^2)=(1)^2/(3)^2=1\/9=1:9`

(ii) Frequency of the sound wave has no effect on amplitude.
so, frequency remains the same if the pitch is unchanged.

∴`"Pitch of first wave"/"Pitch of second wave"`=`1/1`=1 :1.

Concept: Properties of Sounds

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Correct Answer: C

Solution :
We know, \[v=f\lambda \] \[\Rightarrow \]\[f=\frac{f}{\lambda }\]\[\Rightarrow \]\[f\propto \frac{1}{\lambda }\] As wave length ratio = 1 : 3 \[\therefore \]frequency ratio = 3 : 1

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Correct Answer: C

Solution :
\[\lambda =66m\] \[f=?\] \[v=330\text{ }m/s\] We know that \[v=f\lambda \] \[\Rightarrow \]\[f=\frac{V}{\lambda }=\frac{330}{66}=5Hz\]

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Correct Answer: D

Solution :
Not Available

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Correct Answer: D

Solution :
Not Available

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Correct Answer: B

Solution :
Not Available

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Correct Answer: A

Solution :
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Correct Answer: B

Solution :
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Correct Answer: B

Solution :
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Correct Answer: A

Solution :
Not Available

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Correct Answer: A

Solution :
Not Available

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Correct Answer: A

Solution :
Not Available

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Correct Answer: A

Solution :
Not Available

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Correct Answer: D

Solution :
Not Available

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Correct Answer: A

Solution :
Echo is a type of reflected sound

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Correct Answer: A

Solution :
To hear distinct echo, the minimum distance of a reflecting surface should be 17 meters.

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Correct Answer: C

Solution :
Steel will reflect sound better.

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Correct Answer: B

Solution :
Multiple echoes are also called reverberation.

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Correct Answer: C

Solution :
An echo of the sound produced can be heard only if it reaches our ear after\[\frac{1}{10}\]th of second.

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Correct Answer: B

Solution :
Distance of the boy from the wall = 70m distance travelled by sound (before echo is heard) \[=2\times 70m,\]speed of sound\[=350m{{s}^{1}}\] \[Time=\frac{distance}{speed}\] \[=\frac{2\times 70}{350}=0.4s\]

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Page 20

Correct Answer: A

Solution :
\[t=\frac{2}{3}s=1s,\] \[v=330\text{ }m/s,\text{ }s=?\] We know, \[v=\frac{s}{t}\] \[\Rightarrow \] \[s=v\times t=330\times 1=330m\]

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Correct Answer: B

Solution :

Not Available

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Correct Answer: C

Solution :
The intensity of sound is measured in the units of decibel

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Correct Answer: B

Solution :
The characteristic of sound which distinguishes a feable sound from a loud sound of the same frequency is pitch.

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