On what sum of money will the compound interest on certain sum for 2 years at 10% per annum will be Rs 1050?

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A = P$(1+\frac{r}{100}{)}^2$

I = A - P

Hence $I=P(1+\frac{r}{100}{)}^2-P315=P(1+\frac{r}{100}{)}^2-P315=P(1+\frac{10}{100}{)}^2-P315=P(\frac{11}{10}{)}^2-P315=\frac{121P}{100}-P315=P(\frac{121}{100}-1)315=\frac{21P}{100}$

$P=\frac{315\times 100}{21}=\frac{105\times 100}{7}=₹1500$

Therefore, the initial amount = ₹ 1500

Standard VIII Mathematics