Last updated at Oct. 1, 2018 by
Example 1 Construct a triangle ABC, given that AB = 5 cm, BC = 6 cm and AC = 7 cm. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment AB of length 5 cm 2. Taking 7 cm as radius, and A as center, draw an arc. 3. Taking 6 cm as radius, and B as center, draw another arc. Let C be the point where the two arcs intersect Join AC and BC and label the sides Thus, Δ ABC is the required triangle
Dear Student, Please find below the solution to the asked query: We have our diagram from given information , As : Here , AB = 5 cm , BC = 6 cm and AC = 7 cm We know " In any triangle that angle opposite to the larger side is greater than the angle opposite to smaller side. " We have AB < BC , So ∠ ACB < ∠ BAC --- ( 1 ) And we have BC < AC , So∠ BAC < ∠ ABC --- ( 2 ) From equation 1 and 2 we get :∠ ACB < ∠ BAC < ∠ ABC ( Ans ) Hope this information will clear your doubts about topic. If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.Regards
Angle b is largest among all the other angles and the other two angles smaller than angle b.to prove this we should use the axiom "the angle which is opposite to the longest side is largest and the angle which is opposite to shortest side is smallest. |