In a standard deck of cards what is the probability of drawing a black card

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Answer

Hint: In order to solve this problem you need to know that in a deck there are 52 cards and among 52 cards there are 26 black and 26 red cards. Knowing this and using the formula of probability you will get the right answer.

Complete step by step answer:

So, the correct answer is “Option B”.

Note: When you get to solve such problems cards you need to know that A "standard" deck of playing cards consists of 52 Cards in each of the 4 suits of Spades, Hearts, Diamonds, and Clubs. Each suit contains 13 cards: Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King. Knowing these things will solve your problems.

If given a standard deck of 52 cards, what is the probability of drawing a black card on the 1st, 2nd, 3rd, 4th ... $n^{th}$ draw?

I understand that the first is $26/52$, but the second gets a bit more complicated because there is two scenarios:
a) The first draw is black so the probability is $26/52$ * $25/51$
b) The first draw is non-black, so the probability is $26/52$ * $26/51$

I'm not sure what the formulaic expression of this is and how to consider both of these options in one calculation. I know it uses combinatorics, but I'm lost.

Thanks!