Now that we are done with the congruent triangles, we can move on to another concept called similar triangles. Show In this article, we will learn about similar triangles, features of similar triangles, how to use postulates and theorems to identify similar triangles, and lastly, how to solve similar triangle problems. What are Similar Triangles?The concept of similar triangles and congruent triangles are two different terms that are closely related. Similar triangles are two or more triangles with the same shape, equal pair of corresponding angles, and the same ratio of the corresponding sides. Illustration of similar triangles: Consider the three triangles below. If:
AB/PQ = AC/PR= BC= QR, AB/XY= AC/XZ= BC/YZ
Therefore, ΔABC ~ΔPQR~ΔXYZ Comparison between similar triangles and congruent triangles
How to identify similar triangles?We can prove similarities in triangles by applying similar triangle theorems. These are postulates or the rules used to check for similar triangles. There are three rules for checking similar triangles: AA rule, SAS rule, or SSS rule. Angle-Angle (AA) rule: Side-Angle-Side (SAS) rule: Side-Side-Side (SSS) rule: How to Solve Similar Triangles?There are two types of similar triangle problems; these are problems that require you to prove whether a given set of triangles are similar and those that require you to calculate the missing angles and side lengths of similar triangles. Let’s take a look at the following examples: Example 1 Check whether the following triangles are similar Solution Sum of interior angles in a triangle = 180° Therefore, by considering Δ PQR ∠P + ∠Q + ∠R = 180° 60° + 70° + ∠R = 180° 130° + ∠R = 180° Subtract both sides by 130°. ∠ R= 50° Consider Δ XYZ ∠X + ∠Y + ∠Z = 180° ∠60° + ∠Y + ∠50°= 180° ∠ 110° + ∠Y = 180 ° Subtract both sides by 110° ∠ Y = 70° Hence;
Example 2 Find the value of x in the following triangles if, ΔWXY~ΔPOR. Solution Given that the two triangles are similar, then; WY/QR = WX/PR 30/15 = 36/x Cross multiply 30x = 15 * 36 Divide both side by 30. x = (15 * 36)/30 x = 18 Therefore, PR = 18 Let’s check if the proportions of the corresponding two sides of the triangles are equal. WY/QR = WX/PR 30/15 = 36/18 2 = 2 (RHS = LHS) Example 3 Check whether the two triangles shown below are similar and calculate the value k. Solution By Side-Angle-Side (SAS) rule, the two triangles are similar. Proof: 2 = 2 Now calculate the value of k 12/k = 8/4 12/k = 2 Multiply both sides by k. 12 = 2k Divide both sides by 2 12/2 = 2k/2 k = 6. Example 4 Determine the value of x in the following diagram. Solution Let triangle ABD and ECD be similar triangles. Apply the Side-Angle-Side (SAS) rule, where A = 90 degrees. AE/EC= BD/CD x/1.8 = (24 + 12)/12 x/1.8 = 36/12 Cross multiply 12x = 36 * 1.8 Divide both sides by 12. x = (36 * 1.8)/12 = 5.4 Therefore, the value of x is 5.4 mm.
Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion . In other words, similar triangles are the same shape, but not necessarily the same size. The triangles are congruent if, in addition to this, their corresponding sides are of equal length. The side lengths of two similar triangles are proportional. That is, if Δ U V W is similar to Δ X Y Z , then the following equation holds: U V X Y = U W X Z = V W Y Z This common ratio is called the scale factor . The symbol ∼ is used to indicate similarity.
Example: Δ U V W ∼ Δ X Y Z . If U V = 3 , V W = 4 , U W = 5 and X Y = 12 , find X Z and Y Z . Draw a figure to help yourself visualize.
Write out the proportion. Make sure you have the corresponding sides right. 3 12 = 5 X Z = 4 Y Z The scale factor here is 3 12 = 1 4 . Solving these equations gives X Z = 20 and Y Z = 16 . The concepts of similarity and scale factor can be extended to other figures besides triangles.
Given: AB/PQ = BC/QR = AC/PR = 2/3 ΔABC ∼ ΔPQR Calculation: ⇒ ΔABC ∼ ΔPQR So, ⇒ AB/PQ = BC/QR = AC/PR (Corresponding sides of similar triangle are equal in ratio) ⇒ AB/PQ = BC/QR = AC/PR =2/3 ………. (1) And ∠A = ∠P ∠B = ∠Q ∠C = ∠R (Corresponding angles of similar triangle are equal) Now, ⇒ ΔABD and ΔPQS ∠ADB = ∠PSQ (Right angle each) ∠B = ∠Q (given) ⇒ ΔABD ∼ ΔPQS (AA rule of similarity) Therefore ⇒ AB/PQ = AD/PS = BD/QS ……………. (2) From equation (1) and equation (2) ⇒ AB/PQ = AD/PS = 2/3 ∴ The ratio of corresponding altitude is 2 ∶ 3. The correct option is 4 i.e. 2 ∶ 3. The ratio of corresponding sides and the corresponding altitude of 2 similar triangles are equal. India’s #1 Learning Platform Start Complete Exam Preparation
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