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Solution : (i)There are Five digits given: `0,1,2,3,4`<br> At unit place we can have either `1,2,3, or 4`<br> If at first place we have 1, then rest three places can be filled by 5 digits in `5 xx 5 xx 5` ways = `125` ways<br> Again, if we have 2 at first place, then we can fill other digits by 125 ways<br> For 3, again with 125 ways Hence, total numbers formed = `124 + 125 + 125 + 1 = 375` <br> (ii)First place can be filled with Nội dung chính Option 2 : 376 Free History 10 Questions 20 Marks 12 Mins Calculation: The smallest number in the series of 4-digit numbers is 1000. The largest number in the series is 4000, the only 4-digit number to start with 4. The left-most digit (thousands place) of each of the 4 digit numbers other than 4000 can take one of the 3 values 1 or 2 or 3. The next 3 digits Hence, there are 3 x 5 x 5 x 5 = 375 numbers from 1000 to 3999. Including 4000, the numbers will be 375 + 1 = 376. ∴ The number of integers is 376 Skip to content Numbers greater than 1000 and less than or equal
to 4000 will be of 4 digits and will have either 1 (except 1000) or 2 or 3 in the 1st place with 0 in each of remaining places. After fixing 1st place, the 2ndplace can be filled by any of the 5 digits. Similarly the 3rd place can be filled up in 5 ways and 4th place can be filled up in 5 ways. Thus, there will be 5 x 5 x 5 =125 ways in which 1 will be in first place but this alsoincludes 1000. Hence, there will be I 24 numbers having 1 in the first place. Similarly, 125 for each 2 or
3. one number will be there in which 4 will be in the first place, i.e., 4000. Hence, the required number of ways is 124 + 125 + 125 + 1=375. 1) 350 2) 375 3) 450 4) 576 Answer: (2) 375 Solution: There are Five digits given: 0,1,2,3,4 1000<Numbers<4000 At unit place we can have either 1,2,3, or 4. (excluding 1000), where 0 is included. If at first place we have 1, then rest three places can be filled by 5 But we need to exclude 1000, hence, total numbers = 125 – 1 = 124 Again, if we have 2 at first place, then we can fill other digits by 125 ways For 3, again with 125 ways We need numbers, less than 4000, therefore, there will be only 1 possible way Hence, total numbers formed = 124 + 125 + 125 + 1 = 375 Solution : (i)There are Five digits given: `0,1,2,3,4`<br> At unit place we can have either How many number of numbers greater than 1000 but less than 4000 that can be formed by using the digits 0 1,2 3 4 when repetition is allowed?there will be 376 such numbers . What is the number of greater than 1000 but not greater than 4000 that can be formed with the digits 0 1,2 3 4 repetition?Answer: There are 376 numbers. Step-by-step explanation: Given : Numbers greater then 1000 but not greater than 4000 can be formed with the digits 0,1,2,3,4 repetition of digits being allowed. How many numbers greater than 4000 can be formed?Hence, the number of numbers that are greater than 4000 which can be The numbers are: 1024, 1042, 1204, 1240, 1402, 1420, How many 4 digit numbers greater than 1000 can be formed without repetition?From this you can conclude that there are 9*9*8*7 = 4536 ways of choosing the digits without repetition. How many numbers greater than 1000 can be formed by using digits?The numbers are: 1024, 1042, 1204, 1240, 1402, 1420, 2014, 2041, 2104, 2140, 2401, 2410, 4012, 4021, 4102, 4120, 4201, 4210. If repetition of digits is allowed, we can form an infinite number of numbers greater than 1000. Good luck! How many number of numbers greater than 1000 but less than 4000 that can be formed by using the digits 0 1 2 3 4 when repetition is allowed?there will be 376 such numbers . How many 4 digit numbers each greater than 1000 and each having all four digits distinct are there with 7 coming before 3?∴ The 4 digit number greater than 1000 with 7 before 3 is 315. Tải thêm tài liệu liên quan đến bài viết How many numbers greater than 1000 can be made using the following digits without repetition? 1) 350 2) 375 3) 450 4) 576 Answer: (2) 375 Solution: There are Five digits given: 0,1,2,3,4 1000<Numbers<4000 At unit place we can have either 1,2,3, or 4. (excluding 1000), where 0 is included. If at first place we have 1, then rest three places can be filled by 5 digits in 5 x 5 x 5 ways = 125 ways But we need to exclude 1000, hence, total numbers = 125 – 1 = 124 Again, if we have 2 at first place, then we can fill other digits by 125 ways For 3, again with 125 ways We need numbers, less than 4000, therefore, there will be only 1 possible way Hence, total numbers formed = 124 + 125 + 125 + 1 = 375
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How many number of numbers greater than 1000 but less than 4000 that can be formed by using the digits 0 1 2 3 4 when repetition is allowed?
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