Page 2Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles. Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR. `("Area"(triangle"ABC"))/("Area"(triangle"PQR")) = (1/2 xx "AC" xx "BC")/(1/2 xx "PQ" xx "QR")` = `(1/2 xx 5 xx 9)/(1/2 xx 6 xx 10)` = `3/4` Hence, Ratio of Area of △ABC : Area of △PQR = 3: 4. Concept: Similar Triangles Is there an error in this question or solution? |